Long Division of (x^3 - 27) / (x - 3)
Long division is a useful method for dividing polynomials. Let's work through the steps of dividing (x^3 - 27) by (x - 3).
Setting up the Division
- Write the problem:
We include the placeholders (0x^2 and 0x) for the missing terms in the dividend (x^3 - 27) to maintain proper alignment.___________ x - 3 | x^3 + 0x^2 + 0x - 27
Steps of the Division
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Divide the leading terms:
- Divide x^3 (the leading term of the dividend) by x (the leading term of the divisor), resulting in x^2.
x^2 ______ x - 3 | x^3 + 0x^2 + 0x - 27
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Multiply the quotient term by the divisor:
- Multiply x^2 by (x - 3), resulting in x^3 - 3x^2.
x^2 ______ x - 3 | x^3 + 0x^2 + 0x - 27 x^3 - 3x^2
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Subtract:
- Subtract (x^3 - 3x^2) from the dividend.
x^2 ______ x - 3 | x^3 + 0x^2 + 0x - 27 x^3 - 3x^2 --------- 3x^2 + 0x
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Bring down the next term:
- Bring down the next term of the dividend (0x).
x^2 ______ x - 3 | x^3 + 0x^2 + 0x - 27 x^3 - 3x^2 --------- 3x^2 + 0x
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Repeat steps 1-4:
- Divide 3x^2 by x, resulting in 3x.
- Multiply 3x by (x - 3), resulting in 3x^2 - 9x.
- Subtract (3x^2 - 9x) from the previous result.
- Bring down the next term (-27).
x^2 + 3x ______ x - 3 | x^3 + 0x^2 + 0x - 27 x^3 - 3x^2 --------- 3x^2 + 0x 3x^2 - 9x --------- 9x - 27
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Repeat steps 1-4:
- Divide 9x by x, resulting in 9.
- Multiply 9 by (x - 3), resulting in 9x - 27.
- Subtract (9x - 27) from the previous result. The remainder is 0.
x^2 + 3x + 9 x - 3 | x^3 + 0x^2 + 0x - 27 x^3 - 3x^2 --------- 3x^2 + 0x 3x^2 - 9x --------- 9x - 27 9x - 27 --------- 0
Result
Therefore, (x^3 - 27) / (x - 3) = x^2 + 3x + 9.
Important Notes
- The remainder is 0, indicating that (x - 3) is a factor of (x^3 - 27).
- The degree of the quotient is one less than the degree of the dividend.
- Long division is a powerful tool for dividing polynomials, and understanding this process can help you solve various algebraic problems.